7x^2+23x+168=6x^2+3x+7

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Solution for 7x^2+23x+168=6x^2+3x+7 equation: 



7x^2+23x+168=6x^2+3x+7

We move all terms to the left:

7x^2+23x+168-(6x^2+3x+7)=0

We get rid of parentheses

7x^2-6x^2+23x-3x-7+168=0

We add all the numbers together, and all the variables

x^2+20x+161=0

a = 1; b = 20; c = +161;
Δ = b2-4ac
Δ = 202-4·1·161
Δ = -244
Delta is less than zero, so there is no solution for the equation

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